z^2+2Iz-(1-2I)=0

Solution for z^2+2Iz-(1-2I)=0 equation:

Simplifying
z2 + 2Iz + -1(1 + -2I) = 0
z2 + 2zI + (1 * -1 + -2I * -1) = 0
z2 + 2zI + (-1 + 2I) = 0

Reorder the terms:
-1 + 2I + 2zI + z2 = 0

Solving
-1 + 2I + 2zI + z2 = 0

Solving for variable 'I'.

Move all terms containing I to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 2I + 2zI + 1 + z2 = 0 + 1

Reorder the terms:
-1 + 1 + 2I + 2zI + z2 = 0 + 1

Combine like terms: -1 + 1 = 0
0 + 2I + 2zI + z2 = 0 + 1
2I + 2zI + z2 = 0 + 1

Combine like terms: 0 + 1 = 1
2I + 2zI + z2 = 1

Add '-1z2' to each side of the equation.
2I + 2zI + z2 + -1z2 = 1 + -1z2

Combine like terms: z2 + -1z2 = 0
2I + 2zI + 0 = 1 + -1z2
2I + 2zI = 1 + -1z2

Reorder the terms:
-1 + 2I + 2zI + z2 = 1 + -1z2 + -1 + z2

Reorder the terms:
-1 + 2I + 2zI + z2 = 1 + -1 + -1z2 + z2

Combine like terms: 1 + -1 = 0
-1 + 2I + 2zI + z2 = 0 + -1z2 + z2
-1 + 2I + 2zI + z2 = -1z2 + z2

Combine like terms: -1z2 + z2 = 0
-1 + 2I + 2zI + z2 = 0

The solution to this equation could not be determined.